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5n^2+10n-240=0
a = 5; b = 10; c = -240;
Δ = b2-4ac
Δ = 102-4·5·(-240)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-70}{2*5}=\frac{-80}{10} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+70}{2*5}=\frac{60}{10} =6 $
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